pls halp i am autismo i should never have taken maths but my parents will probably kill themselves if i become anything other than an engineer so if not for me help me for their sake
Pls halp i am autismo i should never have taken maths but my parents will probably kill themselves if i become anything...
3/2
-2/3
most likely -(2/3)
this guy (math teacher here)
Negative two thirds
This
log(all the shit on the left side) / log(5)
I'm blanking on the operation...when does the fraction become negative?
19407837821
fucking unhelpful answers.
n = log5(left side of equation)
You should be able to solve this.
Call this number
>Multiply both sides by the denominator, 5^2/3
>Multiplying like bases you add the powers so we get 1 = 5^n+(2/3)
>log both sides to get 0=n+ (2/3)
>subtract 2/3
>n=- 2/3
an denominator can be written as being a numerator to a negative power even if that power is -1
1/2 = 2^(-1)
The bottom part of the fraction is equal to 5^(2/3) because a root is the inverse of a index.
The entire fraction is 1/(5^(2/3)), which is 5^(-2/3) due to reciprocal laws
So you now have 5^(-2/3)=5^n, so it should be obvious now that n=-2/3
1/x = x^(-1)
third_sqrt(x) = x^(1/3)
--
1/(third_sqrt(5))^2 = third_sqrt(5)^-2 = (5^(1/3))^-2 = 5^(-2/3)
=> n = -2/3
...
You stupid fuck.
The cube route of 5 is 5^(1/3)
Square that 5^(2/3)
Reciprocal 5^(-2 / 3)
n = - 2 / 3
Fucking newfag. Post nudes.
-2/3
this is the simplest explanation so far
>Implying being a newfag is somohow linked to not being able to solve an equation
1/((cube root(5))^2) = 1/((5^(1/3))^2) = 1/(5^(2/3)) = 5^(-2/3)
>n = -2/3