Tell me Cred Forumsros, without using l'Hopital's rule, how do you solve the SECOND limit? The correct answer is 2 btw, but I need to show my work
Tell me Cred Forumsros, without using l'Hopital's rule, how do you solve the SECOND limit? The correct answer is 2 btw...
It's zero for no. 2
rationalize the numerator
Multiply by the conjugate.
read the book
the answer is 0 faggot
activate it's almonds
I can only get either the denominator OR the numerator to not equal zero, but for some reason with this question, I can never get both.
DISCLAMER: I AM DRUNK AND HIGH RN.
dtop/dx = -1/(2 rad(5-x))
dbot/dx = -1/(2 rad(x))
Should I continue?
But how?
Imitate the terminator
...
Set sqrt(x) = u then rationalize.
i don't speal English well. but i can explain in russian
Нужно домножить на сопряжённое *(2+sqrt(x))
rationalization the numerator, then factor it into (2+sqrtx)(2-sqrtx)
retard
HOLY SHIT LET ME SUCK YOUR DICK!
fking proff didnt even teach us u-substitution yet! but thank you for the legitimate answer!
here you go
wtf, why is it small >:(
but you used l'hopital's rule
oh, my b. i misread the OP, i thought you said 'to' use l'hopital's rule
not that it's particularly meaningful, since it won't get an A, but not using l'hopital's rule here is just silly. not using LR is just making things unnecessarily complicated. OP should assert that his teacher is a dumby.
so i guess if you wanted to do this without LR, you'd have to rationalize the function with u=√x, but it seems someone else already said that anyway.
I really don't get how rationalizing the numerator, or substituting √x with u will help anything.
Can someone explain in a little more detail please?