Let's see who's got brains

Also estimating here as I don't feel like getting a calculator out. Roughly 96 m^2

90ish

Though I'm genuinely interested in how the fuck you would solve this mathematically to two decimal places. Seems impossibru with the supplied information.

using hax0r mathematic skillz yo

Is it close?

Doesn't matter, its closed nigger.

Mean height x width = 72.3

33,31

96m^2

25.42

Est 92.34m^2

no

how did you get this number

How did you get this number

How did you get this number
....

not an acceptable answer no even looking at that rubbish

no

25.42

Add all widths, divide to find average
Add 2m increments, times it by above number
Then find it's square root figure.

It's one of the easiest math questions I have had to do.

READ THE QUESTION CHILDREN

Well apparently it wasn't that easy because this answer is incorrect.

Thanks for playing though

Midpoint rule...

92,32
dunno if its correct, im bad at maths.. but i just took the average height of the pool, which should be 5.77m and the length is 16m. then just multiple this numbers. is it close? :D

which answer was yours user

71.8222m^2

Well fuck my ass

Took the average of the right side (5) times the distance from 5 to the end (6). = 30
Average of left side (7) times distance (6) = 42
Average of middle (6) times distance (4) = 24

Add them all together = 96 m^2

>
Smallest number = 4.8, Largest number = 7.2. What's at the midpoint of those two numbers? 6! How many 2 meter intervals are there? 8! 2x8=16, 16x6 = 96

close didn't put man on the moon

We are just trying to get an estimate here, it's already a 'close' kind of question. You don't need any more room for error.

650.4
I forgot to multiply by 9 at the end

9.79m2?

80.8m^2

WRONG

Also, make sure you read the question, the answer is to two decimal places

jesus no

think before you throw a number out there, this a pool we are talking about, not an aquarium for whales

96 if midpoint rule tho

how did you get this number

96 is an incorrect answer

Trips for truth

how did you get this number

>put man on the moon
nice meme

68.68 sqm

(40.8/9)*16 =71.822 m^2

how did you get this number

Well I was givin the missues a good rodgering, and she screamed out my name as 9.79 m2 of liquid gushed out onto the floor... and I took it as a sign

Get the length of the connected midpoints, multiply by avg height

just tell them if they're right or wrong, you faggot.

Meant 72.53 m^2

haha well this answer is incorrect, tell her I said hello

Listen up you daft bastards, the answer asks for the measurement in SQUARE METERS.
>What is square root button on calculator

why, my peenus weanus of course :)

hahah! :D

It's my weeeeeenus peanus! :) hahah

ITT: Widths of a swimming pool - my answer is, of course, my peanus weenus :D

hahaha!

JESUS DO YOU RETARDS EVEN HAVE A BASIC GRASP ON MATH? DO YOU KNOW HOW TO DRESS YOUSELVES AND FEED YOURSELVES TOO??

Lol I used to have c++ console programs to do these problems for me. I took c++ 1 the same semester as calc 2. have no idea where the program is now, on some old flashdrive

You seem surprised

80.8 m^2

Python is much better for math problems

I was never really good at math, even in school. I've been out of high school for 8 years, and haven't used anything from that time. So, yeah, not only do I not know any at all how to do the problem in the OP, I no longer give a shit.

The pool is made up of 8 segments that are 2m wide.

The midpoint rule requires that each segment's length is equal to the length of both sides divided by two. So we have the following segment lengths:

Segment 1: (0 + 6.2)/ 2 = 3.1m
Segment 2: (6.2 + 7.2)/2 = 6.7m
Segment 3: (7.2 + 6.8)/2 = 7m
Segment 4: (6.8 + 5.6)/2 = 6.2m
Segment 5: (5.6 + 5)/2 = 5.3m
Segment 6: (5 + 4.8)/2 = 4.9m
Segment 7: (4.8 + 4.8)/2 = 4.8m
Segment 8: (4.8 + 0)/2 = 2.4m

The area of each segment is double the segment length (given its width of 2m). Therefore the total area is simply the sum of the 8 lengths above multiplied by two:

Area = 2m x 40.4m = 80.8 square metres

NOPE haha

I see what you did to get that answer though

80.80 or 72.53 m^2 not sure which method is which.

85.74 square meters

sorry buster but this answer is incorrect

Sorry, it is 80.80 square metres

84 m^2

never learned it, considering it now. I think for this problem the python program wouldn't be much smaller in code lines. My modern physics teacher used python last year for different simulations, I liked the graphing libraries

Again, this answer is INNCORRECT.

Check your math there buddy, I have the answer.

calculate a curve length (sqrt(2+difference)), multiply by height absolute difference, do n times, take sum

i got 95m squared. thats rounded up. i got it by assing all of the 2 meter intervals to find the length of the pool.. thats 16 m. then i added all of the mid lengths then divided my answer by 7 becuase there is 7 intervals. so i multiplied the average width of the pool by its length of 16 = roughly 95m squared

whoops assing --> adding

2*[1/2*[(0+6.2)+(6.2+7.2)+(7.2+6.8)+(6.8+5.6)+(5.6+5.0)+(5.0+4.8)+(4.8+4.8)+(4.8+0)]]=80.8

My math is fine. I know I'm right. You can't prove me wrong.

WRONG

Nigger I told you. (40.8/9)*16 = 72.53m^2

wrong

You really shouldn't take math personally. When you're wrong, try and figure out why, then try again.

Incorrect, sir

wrong, i made that quiz

this had to do sth with integrals right

Amiright?

I dont want to calculate, but is this method good? This midpoint shit was 2 years ago, and we only use integrals now, so i dont recall.

Well if its not 80.80 or 72.53 then you're doing your math wrong.

haha well you better figure out what you're doing wrong, especially if you're designing quizzes

Do your own homework little fag

yes this has to do with integrals, common I wanna see you be the one to answer this

sorry bro i have no idea how to do it

I literally have the answer in front of me, these two answers are incorrect.

Try something else. Especially if you're claiming two answers, you may realize that you don't know what you're talking about...

I'm not taking it personally. I'm saying that I know I'm right, because the midpoint rule is simple as shit and I applied it perfectly.

Stop fucking with people on the internet.

For everyone else, here is a document that shows an answer for this exact problem using Simpson's Rule: orion.math.iastate.edu/rymartin/RUcourses/RU152/hw3_ans.pdf

yeah you need to numerically calculate an integral, and one of the ways to do it is like this:

FFFFFUCK if i know what a midpoint rule is. EU masterrace calculation reporting in.
((6.2+7.2+6.8+5.6+5.0+4.8+4.8)/8)*8 = 46.17m^2 average.

*/7

71.82222

wrong
wrong

90 m^2

You're actually slow

everyone don't forget that the sides of the pool are 0 in length and so you still calculate the sum with them, so it will be (0 + 6.2 + 7.2 + 6.8 + 5.6 + 5 + 4.8*2 +0) = 40.4
divide it by 9 because we count the sides,
40.4 / 9 = 4.488888
and multiply by length which is 16
and we get 71.8222

wrong

Winrar

>wants 2 decimal precision from data with only a tenth in precision
Fucking common core

84.27?

Nigger I said that in the first 20 posts.

>mfw

OPis officially retarded. You divide by 8 not 9. Answer is 80.80

im not doing your home work user.
you do mine.

given: f(x,y)=xsin^2(x+y) find: f xyy

why 8 when you have 9 segments?
delete this

I'm a TA for Calc 3. The answer is absolutely 80.80. Any other answer is wrong, obviously

thats what i got as well but there is only 8 segments not 9 delete this

80.40 m^2

Then you're a shit TA

he's never gonna learn if you give it to him. he can use wolfram.

how are there 8 segments? explain or gtfo

Not really, I'm getting my masters in mathematics. I'm smarter and better at math than you will ever be.

But keep being wrong, it's no skin off my ass when you fail your baby calc 1 homework.

this answer is incorrect, TA.

I never thought someone would ask how to fucking count on Cred Forums

...

prove you are right babyboy

>TA for multi
>thinks he's hot shit
okay

WRONG

wow you guys are really starting to depress me

Fuck off randy you fatass

go suck more dick for cheeseburgers

that literally is the midpoint rule through and through if you think this is wrong then you dont know what the midpoint rule is

you're the one who's begging for help on his easy homework assignment.
post the """""right answer""""" so we can all laugh at you

Lol go ask ur professor then. Don't go thinking you're a bad ass because you're a TA in calc 3. That class is child's play compared to real higher level math courses. Let me know when you take real math courses like analytic number theory or advanced topology.

this.

show us how its done then plz thank you

>a math major with no friends
checks out

this adds too much slack, just average all heights at intervals of 2 including the 0's and multiply by length

aww the babies are getting frustrated, how cute. I know, it's okay, math is harddd.

fucking high schoolers

I've already done those. I'm TA for Calc 3, I'm not taking Calc 3. I've almost got my masters in mathematics.
Maybe you should take Reading for Disadvantaged Adults next semester so you look like less of a fucking moron next time you try to comprehend basic English.

thats not the midpoint rule

the midpoint rule is exactly what I fucking posted

See

this is no longer believable. no one is this much of a prick.

>waah wahh stop being mean to me

sorry

midpoint rule is exactly what is done here

there is no other way to do a midpoint rule but exactly what this user did
go kill yourself

84.27

(3.1+6.7+7.0+6.2+5.3+4.9+4.8+2.4)*2 meters

Whoops, I guess you were right guys, my bad ;o

Trips confirm

poor baby, math is tough I know, have fun on Cred Forums you earned it you tired real hard

this is not the mid point rule you dense fucker

wrong

Agreed I give up

wtf no we're not doing your shitty homework.

>I DONT KNOW HOW TO DO THIS.JPG
>"Hey this is stupid!"

Stop being a fucking math Jew and redistribute the answer

>Let's see who's got brains
With what? Some pre-calculus homework?

89.6

Apparently this isn't unreasonable to ask of Cred Forums, considering 100 people have attempted and not one has been able to answer this correctly, including a "calc 3 TA math major" or whatever the fuck that retard was saying

>100 have attempted
>42 posters
:^)

oh great, one person can count apparently. That's a start Cred Forums

dont need to count newfag

then whats the answer? not good at math can you enlighten me

no it's too fun watching these people who think they're good at math, continually try and fail at a calc II problem

84.27

84.27

nope, sorry guys

Fucking retard i got you wrong look at this fag

here an example for the "TA"

79.77

Can you assure us that the vertical slopes line up with the midpoints of 6.2 and 4.8(the most right one) im not bothering if they are not.

haha lol wut?
>muh vertical slopes

go to bed timmy

yes

wrong