Stupid games for stupid people

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25

All right, everyone show your fucking math.

x + x + x = 21
3(x) = 21
x = 21/3
x = 7 = caterpillar

y + y + x = 19
2(y) + (7) = 19
2(y) + (7) - 7 = 19 - 7
2(y)/2 = 12/2
y = 6 = clock

z + y + x = 15
z + (6) + (7) = 15
z + 13 = 15
z + 13 - 13 = 15 - 13
z = 2 = flower

x + z × y = p
(7) + (2) × (6) = p
Order of operations; PEMDAS
(7) + 12 = p
19 = p

Oh shit, all final variables are slightly different. None of them can be known.

66

You forgot the implied parentheses on the last step. It's:
((7) + (2)) × ((6))=p
(9) × (6)=p
54=p

the bottom caterpillar is different

Attached: Untitled.png (1348x1075, 1.69M)

58

The question at the end uses units not previously introduced. A caterpillar with no flower, a double stack of flowers, and a clock with the hour hand at the 5 o'clock position.
Mechanically speaking, it is impossible to answer that question as these are entirely new elements. Translated, you're asking this;

x + x + x = 21
y + y + x = 19
z + y + x = 15
a + b * c = d
Solve for d

You and your game are inherently flawed and rely on human interpretations, an utter mockery to mathematics and logic alike.

Attached: 20200206_055145.png (1763x1200, 1.56M)

Being that the bottom line is different,
The catepiller is 6
There are 2 flowers, so 4
The clock is set to 5
6 + 4 × 5 = ?
6 + 20 = ?
26

Answer is 12

21/3= 7= caterpillar+flower

19-7= 12
12/2=6 =clock hour when clock hand points at 6

15-13=2=flower

The caterpillar hasn't got a flower, the clock hand points at 3 and there's two flowers.

5+4+3=12

This one is correct

21/3 = 7
19-7 = 12/2 = 6
15 - 13 = 2
7+2x6 = 7+12 = 19
In conclusion OP is a faggot

Bottom line has no same "symbols" as the above 3 lines so it cant be counted?

This

31 :)

the final caterpillar is caterpillar - flower aka 4

15

7+7+7=21
6+6+7=19
2+6+7=15
5+(2x5)=15

no wait, that's 2 flowers on the bottom (it's bad compression) so that's 5+(4x5)=25

48 idiots

but the caterpillar with flower is 7.. 7-2 is 5 you fucking mongoloid.

19

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